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cot(108^0) A) 2.47 B) -0.32 C) 0.41 D) -3.08 i need to learn how to do the cot
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cotx=1/tan x
find tan(108) then take the reciprocal
= cos(108)/sin(108)
its 2nd quadrant so will be negative
i thought 1/tan = cos/sin @Krishnadas
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tan = sin/cos so the reciprocals are are you have written
@arria both are same
tanx=sinx/cosx ---->cotx=1/tanx=cosx/sinx
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