Question

HELP!!! URGENT!!! For -1 ≤ x ≤, F(x) = integral of the square root of
1 - t^2 dt from -1 to x.

a. What does F(1) represent geometrically?
b. Find F'(x).

Answer 1

\[\int\limits_{-1}^{x}\sqrt{1-t^{2}}dt\]

Answer 2

it looks like a circle of radius 1

Answer 3

u can find the derivative qith the fundamental theorem of calculus just replace t by x