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OpenStudy (anonymous):
if sin x=1/2 and cos x=√3/2, evaluate the following function: tan x
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OpenStudy (ankit042):
tanx = sinx/cosx now you can solve
OpenStudy (anonymous):
tanx=1/2/( root3/2)
OpenStudy (anonymous):
can you help with another one like that? csc x= (4√3)/3 and cos x<0, evaluate the function below: sin x
OpenStudy (anonymous):
@ankit042
OpenStudy (ankit042):
sinx = 1/cosecx
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OpenStudy (anonymous):
csc x=1/sinx
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