Question

Given: line DR tangent to Circle O.

If m arc DB = 150°, then angle A =

Answer 1

210 is not an answer choice

Answer 2

By inscribed angle theorem it should be \[105^0\]

Answer 3

thanks got it

Answer 4

\[\angle A =\frac{1}{2} \times [360^0-m(arc BD)]=\frac{1}{2} \times [360^0-150^0]\]
\[\angle A =\frac{1}{2} \times [360^0-m(arc BD)]=\frac{1}{2} \times 210^0 =105^0\]