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Find the area of the triangle with A = 41°, b = 22 in, and c = 36 in.
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Of you have two sides and the angle BETWEEN them, then the formula is |dw:1374688213938:dw| \[\text{AREA} = \frac{1}{2}a*b*Sin(C)\]
so .5*22*36*sin31 ?
i got 203.9
Almost correct. You just misread the problem. At least, up there you had it as 41 degrees, not 31.
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