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Calculus1
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Please help! question below *medal and fan*
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\[\int\limits_{\sqrt{2}}^{2} \ \frac{ dx }{ x \sqrt{x ^{2}-1} }\]
i know the final answer is pi/12 but i dont know how to get it
do u know trigonometric substitution?
kinda
isnt the integral of \[\frac{ 1 }{ x \sqrt{x ^{2}-1} }\] equal to sec^-1??
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yes
so now i do sec^1(2) - sec^-1(sqrt(2))???..
@julian25
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