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Solve the following system of equations. 2x – 3y + z = –1 3x + 2y + 2z = –1 x – y – 3z = –4 not really getting how to do this cause i keep hitting dead ends.
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z=1 x=-1 y=0
my answer choices are a. (–1, 0, 1) b. (1, 1, 4) c. (–1, –1, –2) d. (1, 2, 1)
so a?
nevemind got it thanks a bunch!
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