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Mathematics 20 Online
OpenStudy (bekkah323):

factor completely: 4x^3+ 12x^2-9x-27 I think i use grouping but I'm not sure?

OpenStudy (bekkah323):

\[4x^3+12x^2-9x-27\]

OpenStudy (bekkah323):

the book gave me the answer (2x+3)(2x-3)(x+3) i just don't know how they got there

OpenStudy (uri):

4x^3+12x^2-9x-27 4x^2(x+3)-9(x+3) (x+3)*4x^2-9)

OpenStudy (bekkah323):

but how do you get to (2x+3)(2x-3)(x+3)

OpenStudy (uri):

Well i combined them (x+3) (x+3) =(2x+3) and 4x^2-9 =(2x-3)(2x-3)

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