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Mathematics 6 Online
OpenStudy (anonymous):

The sum of the squares of 3 consecutive positive integers is 116. What are the numbers? Which of the following equations is used in the process of solving this problem? a) 3n2+ 5 = 116 b) 3n2+ 3n + 3 = 116 c) 3n2+ 6n + 5 = 116

OpenStudy (anonymous):

\[n^2+(n+1)^2+(n+2)^2=116\] right?

OpenStudy (anonymous):

i get \(3 n^2+6 n-111 = 0\)

OpenStudy (anonymous):

which i guess is the same as C

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