A spinner is divided into equal segments. Each segment is numbered and one segment is labeled with "Free Spin." Isaiah spins the spinner ten times and never gets an odd number. What is the probability that he will get an odd number on the eleventh try?

Question

A spinner is divided into  equal segments. Each segment is numbered  and one segment is labeled with "Free Spin." Isaiah spins the spinner ten times and never gets an odd number. What is the probability that he will get an odd number on the eleventh try?

directrix · Answer

Are these your options:

A) 50%
 B) 51%
 C) 60%
 D) 100%

directrix · Answer

Here's the same problem as posted a year ago on OpenStudy. http://openstudy.com/study#/updates/4e765eb90b8b7d4f6d0257fc

directrix · Answer

I agree with the work of @jack at http://tinyurl.com/n6xx9jn ---------- 5 Odd segments 1, 3, 5, 7, 9 5 Non-odd segments 2, 4, 6, 8, Free Spins from the past have no influence on future spins, so the chance is 5/10 = 50%

directrix · Answer

@s0fl0