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Mathematics 8 Online
OpenStudy (anonymous):

arctan(tan(7pi/6)) ?

OpenStudy (anonymous):

=pi/6 just calc that

OpenStudy (anonymous):

-pi/6, right?

OpenStudy (anonymous):

i dont understand why though?

OpenStudy (anonymous):

or that it doesn't matter

OpenStudy (anonymous):

oh i see. because tangent boundary is between pi/2 and 3pi/2..also can it be 11pi/6, or does that not work?

OpenStudy (anonymous):

arctan[tan(x)] = x only when -π/2 < x < π/2

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

so we must find out tan(7pi/6)

OpenStudy (anonymous):

yes, but 11pi/6 falls in between -pi/2<x<pi/2

OpenStudy (anonymous):

oh waitttt i see. nm

OpenStudy (anonymous):

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