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arctan(tan(7pi/6)) ?
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=pi/6 just calc that
-pi/6, right?
i dont understand why though?
or that it doesn't matter
oh i see. because tangent boundary is between pi/2 and 3pi/2..also can it be 11pi/6, or does that not work?
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arctan[tan(x)] = x only when -π/2 < x < π/2
right?
so we must find out tan(7pi/6)
yes, but 11pi/6 falls in between -pi/2<x<pi/2
oh waitttt i see. nm
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