Question

Line BC is tangent to circle A at B and to circle D at C. What is AD to the nearest tenth?

A. 21.6
B. 18.1
C. 19.3
D. 18.7

Answer 1

ok i will tell you the method

Answer 2

ready??:D

Answer 3

you here?

Answer 4

respond @linhsanityy

Answer 5

Draw a line from A to C..Since BC is a tangent to circle A at B.it is perpendicular to the radius.So angle B is 90 degrees

Answer 6

so we can use pythagorus theorem and find AC= \[\sqrt{18^2+7^2} \approx19.3\]

Answer 7

Now use pythagorus theorem again \[AC^2=5^2+AD^2\]

Answer 8

\[(19.3)^2-25=AD^2\]

Answer 9

AD=18.7

Answer 10

you got it @linhsanityy ?

Answer 11

sorry for the late response >_< but yea i got it thank you so much!! @krishnadas