Question

Solve for variable:
log(x)+log(x+3)=3
log(x^2+3x)=3
10^3=x^2+3x
How do you solve for x?

Answer 1

10^3 = 1000 = x^2+3x
so
x^2 + 3x - 1000 = 0

Answer 2

(x+(3/2))^2 = 1000 + 9/4
x+(3/2) = +- sqrt(4009/4)
x = +- sqrt(4009/4)-(3/2)

Answer 3

\[x=-\frac{3}{2}\pm \sqrt{\frac{4009}{4}}\]

Answer 4

Thank you @zzr0ck3r