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OpenStudy (anonymous):
Find all solutions in the interval [0, 2π). 2 sin2x = sin x Answers: x = π/3, 2π/3 x = π/2, 3π/2, π/3, 2π/3 x x = pi divided by two, three pi divided by two., pi divided by three., two pi divided by three. x = 0, π, pi divided by six, five pi divided by six x = pi divided by six, five pi divided by six
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