Question

Find all solutions in the interval [0, 2π).

2 sin2x = sin x

Answers:
x = π/3, 2π/3
x = π/2, 3π/2, π/3, 2π/3
x

x = pi divided by two, three pi divided by two., pi divided by three., two pi divided by three.

x = 0, π, pi divided by six, five pi divided by six

x = pi divided by six, five pi divided by six