SQ bisects TSR. Find the value of X.

http://gyazo.com/c5f939af9bcb0e068374d6ca85fb0c43

Question

SQ bisects TSR. Find the value of X.

http://gyazo.com/c5f939af9bcb0e068374d6ca85fb0c43

directrix · Answer

The triangles are congruent by HL Theorem or you could argue AAS Theorem. That means that corresponding sides are congruent.

directrix · Answer

Sides TQ and QR are congruent. 

So, solve the equation:

8x + 20 = 10x

@GeometryHelpPlz 

Post what you get for x, and we will compare answers. Okay?

anonymous · Answer

I got 8x+20=10x so combine like terms x=10

anonymous · Answer

because 10x-8x=2x and you would 20/2x so x=10

anonymous · Answer

Am i correct?

directrix · Answer

Yes, x = 10.

anonymous · Answer

Oh Okay i was kind of lost on that one ha. it was a duh question though

directrix · Answer

There was more information given than was necessary to solve the problem. That made it confusing. I had to look three times myself. All that stuff about the angle bisector was totally unnecessary.