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A rectangle has length 4x –1 and a width 2x + 1 -a) Show how to find the perimeter of the rectangle b) Simplify the expression. -a) Write an algebraic expression for the area of the rectangle b) Simplify the expression - If the area of another rectangle is x2 + 5x + 4, find algebraic expressions representing possible lengths and widths of the rectangle.
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perimeter=2(l+b)=2( (4x-1)+(2x+1) )
perimeter=2(4x+2x+0)=2(6x)=12x
area = 8x^2+2x-1
is that for the last one?
when we factorize x^2+5x+4 we get (x+4)(x+1) so the possible lengths are (x+4) and (x+1)
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no thats the b part of ques 2..i accedently deleted its a part
its a part is area=(4x-1)(2x+1)
Thank you so much!!
my pleasure:D
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