Question

how do I factor 4x^2-9=0

Answer 1

(2x+3)(2x−3)

Answer 2

@kyusakazaki : nice bro

Answer 3

stgreen, I sort of remember that yes.

Answer 4

stgreen, yes.

Answer 5

\[(a ^{2}-b ^{2})=(a+b)(a-b)\]
Here, \[4x ^{2}-9\] can be written as \[(2x) ^{2}-3^{2}\]
So, \[(2x) ^{2}-3^{2}=(2x+3)(2x-3)=0\]

Answer 6

thanks everyone! thanks so much! still going to fail this final, but at least i'll have a few problems up my sleeve!

Answer 7

anyone know how to find a horizontal asymptote?