Mathematics
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OpenStudy (colcaps):
Given: f(x) = 2x2 – 3x + 4 g(x) = x + 3
Find: (f+g)(x)
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OpenStudy (anonymous):
(f+g)x=f(x)+g(x)
OpenStudy (anonymous):
2x^2-2x+7
OpenStudy (colcaps):
So do i replace it with the given and solve it all in?
OpenStudy (anonymous):
yup..
OpenStudy (anonymous):
add both
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OpenStudy (colcaps):
alright let me try it, i'll solve.
OpenStudy (anonymous):
got it?
OpenStudy (colcaps):
Wait, i got confused in the second equation from the first equation
OpenStudy (colcaps):
2x^2 is 4x right?
OpenStudy (anonymous):
\[2x^2-3x+4+x+3=2x^2-2x+7\]
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OpenStudy (anonymous):
no no..
OpenStudy (colcaps):
combine like terms?
OpenStudy (anonymous):
there is no need to "SOLVE" this
OpenStudy (anonymous):
i thought you were talking about combining
OpenStudy (colcaps):
so ill just subtract and add?
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OpenStudy (colcaps):
pardon me, im not good with math
OpenStudy (anonymous):
ya..
OpenStudy (anonymous):
jus like numbers
OpenStudy (colcaps):
so lets go back to our equation,2x^2-2x+7 so what will i do first sine it has "x" in it?
OpenStudy (colcaps):
*since
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OpenStudy (colcaps):
I mean the 2x^2
OpenStudy (anonymous):
no need to do anything..We wont have to find the x
OpenStudy (colcaps):
2-2 +7?
OpenStudy (anonymous):
what we wrote is the answer
OpenStudy (colcaps):
OH!
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OpenStudy (anonymous):
got it?
OpenStudy (colcaps):
do you still need to solve it when you distribute the given to the question?
OpenStudy (anonymous):
Actually we dont solve it unless we are told to find (f+g)(3),(f+g)(4) and stuff...then we substitute that value to our x's
OpenStudy (anonymous):
suppose you are told to find (f+g)(3) then the answer will be 2(3^2)-3(3)+7 =18-9+7=16
OpenStudy (colcaps):
isnt it suppose to be written like this? (2x^2-3x+4+x+3) And what is "(x)"?
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OpenStudy (anonymous):
yeah...-3x+x=-2x and 4+3=7..so we wrote it simply like our answer
OpenStudy (anonymous):
you dont have to know what is x
OpenStudy (colcaps):
Waht happened to 2x^2? wow im really confused right now.
OpenStudy (anonymous):
it is there..our final answer is \[2x^2-2x+7\]
OpenStudy (anonymous):
FINAL!!!
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OpenStudy (colcaps):
Alright, lets go back because we are having a quiz on functions, ill try to answer this alright?
OpenStudy (colcaps):
Given: f(x) = 2x2 – 3x + 4 g(x) = x + 3
Find: (f+g)(x)
OpenStudy (anonymous):
ok..nothing special happened here..we just added both functions
OpenStudy (colcaps):
So ill distribute the given to my equation right?
OpenStudy (anonymous):
distribute?what do you mean?
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OpenStudy (colcaps):
I mean replace it or something
OpenStudy (anonymous):
no..actually we had our final answer..now u dont need to do anything
OpenStudy (colcaps):
Hahaha alright, thanks for helping, ill try to review the steps ey'
OpenStudy (anonymous):
are you thinking of substituting a value to x?
OpenStudy (colcaps):
No, i mean the given will be written in the "(f+g)(x)" problem
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OpenStudy (anonymous):
we found the (f+g)(x)
OpenStudy (colcaps):
so (f+g)(x) is = to (2x^2-3x+4+x+3) right?
OpenStudy (colcaps):
also, whats the "(x)"?
OpenStudy (anonymous):
oh (x)?
OpenStudy (colcaps):
yeah
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OpenStudy (anonymous):
(x) is just the symbol..it has no value
OpenStudy (anonymous):
you can give any value to it
OpenStudy (colcaps):
so what will i do with it?
OpenStudy (anonymous):
(f+g)(x) is just like writing (f)(x)
OpenStudy (anonymous):
(f+g)and (x) are not seperate things
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OpenStudy (colcaps):
Alright, last question, what is 2x^2-3x+4+x+3... So its
=4x-3x+4+x+3
=1x+4+x+3
Am i doing it right?
OpenStudy (colcaps):
if yes, should i continue?
OpenStudy (anonymous):
2x^2 is not 4x
OpenStudy (colcaps):
why?
OpenStudy (anonymous):
2x^2=2x^2
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OpenStudy (anonymous):
4 is 2^2
OpenStudy (anonymous):
it is 2*(x^2)
OpenStudy (anonymous):
not 2^2 * (x)
OpenStudy (colcaps):
You seperated x^2?
OpenStudy (anonymous):
ya..2 and x^2 are different
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OpenStudy (anonymous):
sorry i need to go..bye
OpenStudy (colcaps):
2x^2-3x+4+x+3
=2(x^2)-3x+4+3=x
is that right?
OpenStudy (colcaps):
Alright, thanks
OpenStudy (anonymous):
@Colcaps
OpenStudy (anonymous):
you got 2x^2-3x+4+x+3?
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OpenStudy (colcaps):
Yes
OpenStudy (anonymous):
2x^2-3x+4+x+3
=2(x^2)-3x+4+3=x ???
it should be this..am i right @Krishnadas 2x^2-2x+7..
OpenStudy (anonymous):
ya you are right @pengembara_bumi1 ...
OpenStudy (anonymous):
so @Colcaps now add -3x and x
OpenStudy (anonymous):
ouh,thanks..hehe ^_^
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OpenStudy (colcaps):
-2x?
OpenStudy (anonymous):
ya..now add 4 and 3
OpenStudy (anonymous):
@Colcaps
OpenStudy (anonymous):
7
OpenStudy (colcaps):
4+3 is 7 yeah
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OpenStudy (colcaps):
@Krishnadas
OpenStudy (anonymous):
so what are the terms left,2x^2 ,-2x and +7
OpenStudy (anonymous):
adding them gives our final answer
OpenStudy (colcaps):
2-2+7=x?
OpenStudy (anonymous):
no 2x^2-2x+7
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OpenStudy (anonymous):
which equals (f+g)(x)
OpenStudy (anonymous):
got it?
OpenStudy (colcaps):
OH!
OpenStudy (anonymous):
why is there a doubt?:D
OpenStudy (anonymous):
okay??
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OpenStudy (colcaps):
I thought youll look for the result of it so i got really confused
OpenStudy (colcaps):
Thank you for teaching me mate, that means alot
OpenStudy (anonymous):
this is our result..2x^2-2x+7
OpenStudy (anonymous):
Happy to help:D
OpenStudy (colcaps):
i have another question but its harder than this, ill make a new one
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OpenStudy (anonymous):
ok