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Why can't (x + 3) and (x - 3) both be factors of x2 - 6?
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because when you expand it. it will become x2-9..
The constant terms of the binomials do not add up correctly? is that right?
Because 3 times -3 equals -9, not -6.
\[3\times 3 \neq 6\]
x^2-6=(x-sqrt6)(x+sqrt6)
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The constant terms of the binomials are not factors of the constant term of x2 - 6?
Because right now i am lost in the sauce
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