Write the equation of the line that is parallel to the line 3x − y = −3 and passes through the point (4, −2).
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OpenStudy (anonymous):
you need to put your equation in y = mx + b form.
Can you do that ?
OpenStudy (anonymous):
@Devind23
OpenStudy (anonymous):
y=3x+3
OpenStudy (anonymous):
parallel to this line means same slope
OpenStudy (anonymous):
slope=3
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OpenStudy (anonymous):
so by point slope form,the eqn. is (y--2)=3(x-4) ----->y+2=3x-12
OpenStudy (anonymous):
y-3x=-14
OpenStudy (anonymous):
or y=3x-14
OpenStudy (anonymous):
got it?
OpenStudy (anonymous):
Thank you
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OpenStudy (anonymous):
you are welcome:D
OpenStudy (anonymous):
Can you help me out with my next 2 questions? They're the same just different numbers
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).
OpenStudy (anonymous):
here slope=2....the slope of the perpendicular line should be negative reciprocal of this..so our line has a slope -1/2...(y-3)=(-1/2)(x-6)
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OpenStudy (anonymous):
jus expand it
OpenStudy (anonymous):
y+1/2 x=6
OpenStudy (anonymous):
So it's Y= -1/2 + 6?
OpenStudy (anonymous):
-1/2 x
OpenStudy (anonymous):
you forgot the x
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OpenStudy (anonymous):
Okay got it. Next question
OpenStudy (anonymous):
Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).
y = x − 10
y = x + 10
y = −x − 10
y = −x + 10
OpenStudy (anonymous):
divide this line eqn by 3 so we get y= (2/3 x)-1
OpenStudy (anonymous):
slope of our line will be -3/2 ......(y-2)= -3/2 (x+8)
OpenStudy (anonymous):
I am getting y=(-3/2)x -10..but
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OpenStudy (anonymous):
So the first one?
OpenStudy (anonymous):
no..
OpenStudy (anonymous):
its not in the options
OpenStudy (anonymous):
Oh the fractions from the questions didn't come up its there
OpenStudy (anonymous):
is it -3/2
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OpenStudy (anonymous):
Okay last one
OpenStudy (anonymous):
2x - 3y = 3
-3y = -2x + 3
y = -2x/-3 + 3/-3
y = 2/3x - 1
perpendicular is negative reciprocal
slope will be -3/2
y - y1 = m(x - x1).........(-8,2)
y - 2 = -3/2(x -(-8)
y - 2 = -3/2x + 8
y = -3/2x + 10
OpenStudy (anonymous):
k
OpenStudy (anonymous):
Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6).
y = x + 7
y = −3x + 3
y = x + 3
y = −3x + 7
OpenStudy (anonymous):
1/3x is in the first and third answer
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OpenStudy (anonymous):
slope =-3...(y-6)=-3(x+1) --->y=-3x+3
OpenStudy (anonymous):
Thank you so much! Dude whats your number just in case I have more trouble lol
OpenStudy (anonymous):
I will be here..
OpenStudy (anonymous):
or mail to dasuttan03@gmail.com
OpenStudy (anonymous):
okay..?
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