Question

To solve a trigonometric equation:

Answer 1

\[\sqrt{3}sinx = \frac{ 1 }{ 2 } secx\]

Answer 2

\[2\sqrt{3}sinx = secx\]

Answer 3

\[2\sqrt{3}sinx - \frac{ 1 }{ cosx } = 0\]

Answer 4

Now where do I go?

Answer 5

now you find for which values of x make \[2\sqrt{3}\sin x=\frac{ 1 }{ cosx}\]

true.


it's easiest just to look at a unit circle