Question

Find all solutions in the interval [0, 2π).

4 sin2x - 4 sin x + 1 = 0

I'd like to know the identities used and how you came to know which one to use.

Answer 1

(4 sin^2x) - 4 sin x + 1 = 0

Answer 2

youd use the quadratic equation ....

Answer 3

let u = sin(x)

Answer 4

4 sin^2 x - 4 sin x + 1 = 0

4 u^2 - 4u + 1 = 0

solve for u to determine sin(x)

Answer 5

Wow... I feel dumb. Thank you very much!

Answer 6

youre welcome

Answer 7

Where do I go from (2u-1)^2 = 0?