Question

Find all solutions in the interval [0, 2π).

4 sin^2x - 4 sin x + 1 = 0

I've factored but I don't know what to do from here:
Where do I go from (2sin-1)^2 = 0?

Answer 1

2sinx - 1 = 0
Sinx = 1/2
X = pi/6 Or x = 5Pi/6