Question

What is the equation of a line that passes through the point (-2,1) and (1,10)?

3X-Y=-5
X+3Y=-5
3X-Y=-7
3X-Y=5

Answer 1

required equation is
y-y1=((y2-y1)/(x2-x1))(x-x1)

Answer 2

x1=-2
y1=1

Answer 3

\[\frac{ y2-y1 }{ x2-x1 }=\frac{ y-y1 }{ x-x1 }\]

Answer 4

x2=1
y2=10

Answer 5

can you please keep going so I can see this problem done as an example?

Thanks!

Answer 6

slope of ur line is
m=(y2-y1)/(x2-x1)

Answer 7

I dont understand?

Answer 8

y-1=(9/3)(x+2)
y-1=3(x+2)
y-1=3x+6
y=3x+7

Answer 9

3x-y=-7

Answer 10

c my work once again