Question

What is the vertex of the parabola y = 5(x - 4)^2 - 1 ?

Answer 1

\(\large y=5(x-4)^2-1\)

So your parabola is in .. standard form or whatever it's called :3

\(\large y=(x-h)^2+k\)

Where our vertex is located at \(\large (h,k)\).