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Mathematics 7 Online
OpenStudy (nptweezy):

ASAP (Medal + Fan) Does anyone know what this is (pic)

OpenStudy (nptweezy):

THIS

OpenStudy (anonymous):

Option A is correct

OpenStudy (anonymous):

I Agree With A .

OpenStudy (anonymous):

Hows that?

OpenStudy (anonymous):

\[(4^2b^3c^{-5})(4^{-1}b^{-4}c^{8}) \] \[=4^{2-1} b^{3-4}c^{-5+8}=4 b^{-1}c^3= \frac {4c^3}{b}\]

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