Question

the iterative formula (which will be inserted) gives a sequence which converges to (formula 2).

Answer 1

\[x_{n+1} = \frac{ 1 }{ 2 } (\ln 9 - \ln x _{n})\]

Answer 2

formula 2: \[x = 9e ^{-2x}\]

Answer 3

\[\frac{ 1 }{ 2 } (\ln 9 - \ln x _{n})\]
\[\frac{ 1 }{ 2 }\ln \frac{9}{x_n}\]
\[\ln \frac{3}{\sqrt{x_n}}\]

Answer 4

Ok, I got it, thanks!