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Solve the following quadratic equation using the quadratic formula. Which of the following expressions gives the numerators of the solutions? 10x^2 - 19x + 6 = 0 a) -19 ± 11 b) 19 ± 11 c) 19 ± 12
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a = 10 b = -19 c = 6 \[\frac{b \pm \sqrt{b^2 - 4ac}}{2a}\]
a?
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