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If the quadratic formula is used to find the solution set of 3x^2 + 4x - 2 = 0, what is the result of substituting in the values? I got -4 (plus or minus) the sqrt of 8 over 6
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oops
what?
\[b^2-4ac=4^2-4\times 3\times (-2)\]
that is \(16+24=40\)
so -4(plus or minus) the sqrt of 40 over 6?
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yeah
thanks
but you are not actually done
that's all it has in my options
it didn't say to go any further
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ok then you ARE done
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