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What is the solution set of (3x - 1)2 = 5?
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i take it this is \[(3x-1)^2=5\] right?
so \[3x-1=\pm\sqrt5\] and so you get \[3x=1\pm\sqrt5\] making \[x=\frac{1\pm\sqrt5}{2}\]
oops typo there \[x=\frac{1\pm\sqrt5}{3}\]
if you have \[(ax+b)^2=c\] do not multiply out and use the quadratic formula, that is working backwards
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