Question

Verify the identity, show all work
tanθ cotθ-sin^2 θ=cos^2 θ

Answer 1

tanθ = sinθ/cosθ and cotθ = cosθ/sinθ. So I'll rewrite your problem now
(sin/cos)*(cos/sin) - sin^2θ = cos^2θ
The multiplication cancels and becomes 1. So now you have your pythagorean theorem identity, 1- sin^2θ = cos^2θ, which is of course true.

Answer 2

@Psymon can you help me with these 3? All that you can/ want to do anyway

1/(1+sinx)+1/1+cscx)=1

(1-2sin^2 θ)/(sinθcosθ)=cotθ-tanθ

√([1+sinθ]/[1-sinθ])=(1+sinθ)/|cosθ|

thank you so, so much!

Answer 3

^^those are all for verifying the identity