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what's the trig identity for sin^2(x) = ? so that I can integrate it.
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(1-cos2x)/2
yes. thank you!
:3
recall $$\cos2x=\cos^2 x-\sin^2x=1-\sin^2x-\sin^2x=1-2\sin^2 x$$Solving for \(\sin^2 x\) we have:$$2\sin^2 x=1-\cos 2x\\\sin^2 x=\frac12(1-\cos 2x)$$
true. Unfortunately this is part of a much bigger problem and I didn't want to go to all that trouble :)
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