Which is an equation of a circle with center (5, 0) that passes through the point (1, 1)?

(x - 1)^2 + (y - 1)^2 = 17
(x - 5)^2 + y^2 = 17
(x + 5)^2 + y^2 = 17
(x + 5)^2 + y^2 = 24

Question

Which is an equation of a circle with center (5, 0) that passes through the point (1, 1)?
 	
	(x - 1)^2 + (y - 1)^2 = 17
	(x - 5)^2 + y^2 = 17
	(x + 5)^2 + y^2 = 17
	(x + 5)^2 + y^2 = 24

agent0smith · Answer

Center (5,0) means the equation has to look like this:

(x-5)^2 + y^2 =

anonymous · Answer

17

agent0smith · Answer

So... you can already eliminate three answers and don't need to use the point (1,1) at all!

agent0smith · Answer

If you did though, you'd plug in x=1 and y=1:

(1-5)^2 + 1^2 = 17
(-4)^2 + 1 = 17
16 + 1 = 17

which is true :)

anonymous · Answer

yay ok thank you :)

agent0smith · Answer

Welcome emuhleeeee!