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Solve the equation: sqr3 sinx = 1/2 sec x
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\[\sqrt{3} \sin x = \frac{ 1 }{ 2 } \sec x\]
@amistre64
2 sqr3 sinx = sec x 2 sqr3 sinx cosx = 1 2 sinx cosx = 1/sqrt3 sin(2x) = 1/sqrt3
2x = arcsin(1/sqrt3) x = arcsin(1/sqrt3)/2 = .30773....
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does that make sense? or did i just do your work?
No, not at all. :) That does make sense. I thought there were supposed to be 2 answers to the question, so I was getting confused, and I kept the 2 apart from the sinxcosx. Now I remember 2 sinxcosx does equal sin2x.
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