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evaluate 8 (sigma symbol) n+25 n=3
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\[\Large \sum_{3}^{8} n+25\] This means you want the sum of n+25, starting from n=3 and stopping at n=8: \[\Large \sum_{3}^{8} n+25 =\]\[ (3+25) + (4+25) + (5+25) + (6+25) + (7+25) + (8+25)=\]
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