Question

The graph of y = ax^2 + bx + c is a parabola that opens up and has a vertex at (-2, 5). What is the solution set of the related equation 0 = ax^2 + bx + c?

a) Ø
b) {-2}
c) {5}

Answer 1

(x + 2)^2 + 5 = 0 is the equation in vertex form
can you continue from here?

Answer 2

-2?

Answer 3

expanding

x^2 + 4x + 4 + 5 = 0
x^2 + 4x + 9 = 0

there are no real solutions to the

so a) is correct

Answer 4

oh... thanks!