Help me, walk me through the process please!!!!
well, the line equation is \(\bf y = -3x + 1 goes through the points (1, a) and (b, 4) so we know that x y ( 1, a ) ( b, 4 )
well, the line equation is \(\bf y = -3x + 1\) goes through the points (1, a) and (b, 4) so we know that x y ( 1, a ) ( b, 4 )
yes, that I understand
if you want to know what "a" is well, at when (1, a) when x = 1, y = a in y = -3x+1, so let's use those values ( a ) = -3( 1 ) + 1 #solving for "a", what would it give? -------------------------------------- at (b, 4) when x = b, y = 4, in y = -3x+1, so let's use those values ( 4 ) = -3( b ) + 1 #solving for "b" what would it give?
-2 and then -11?
( a ) = -3( 1 ) + 1 a = -3 + 1 a = -2 --------------------------- ( 4 ) = -3( b ) + 1 4 = -3b + 1 # substracting 1 from each side 3 = -3b # dividing by -3 each side -1 = b
oops lol sorry yes b=-1
so, now if you want to know what 2a-3b = just plug in the values for "a" and "b"
okay
-3
2 ( -2) - 3 ( -1)
oopppps i put -3 for x... ok so its -1?
yes
alrighty lol thank you so much!!!!
yw
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