Jake's band played songs at three different parties. At the first party they played four-fifths as long as they did at the second party, which was one-half as long as the third party. If they played for 6 minutes at the first party, how many minutes did they play at the third party?

2 minutes

four and four-fifths minutes

eight and three-fifths minutes

fifteen minutes

Question

Jake's band played songs at three different parties. At the first party they played four-fifths as long as they did at the second party, which was one-half as long as the third party. If they played for 6 minutes at the first party, how many minutes did they play at the third party?

 2 minutes

 four and four-fifths minutes

 eight and three-fifths minutes

 fifteen minutes

anonymous · Answer

@vipergirl81 ...

anonymous · Answer

So to make it all a bit simpler, you represent the first party as 'a', second party as 'b' and third party as 'c'.
a=4/5b
c = 1/2 b

since a=6,
6=4/5(b)
b=7.5

c=2(7.5)
c=15

So they played 15 minutes at the third party.

anonymous · Answer

Sorry it took so long. I got messed up in the middle and had to retype everything.

anonymous · Answer

@vipergirl81 thank you so much and thanks for the explaintion too!

anonymous · Answer

no problem!