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how do you get the exponential form of log[4](x)=32? explain step by step
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4 is the base= the number raised by the exponent x is the exponent 32 is the answer so 4^x=32 x=2.5
@TheDoctorRules
Woops. Sorry, x is the answer and 32 is the exponent :P
Remember the key equivalency for this kind of problem:\[a^x=y \iff \log_ay=x\]In this case, we are starting with the right hand side, and changing it to fit the left hand side. For this problem,\[\log_4(x)=32 \iff 4^{32}=x\]
do you understand it now ?
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