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OpenStudy (anonymous):
Verify the identity: [sin(3t)-sin(t)]/[cos(3t)+cos(t)]=tan(t)
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OpenStudy (anonymous):
For sin: sin(3t)*cos(t)-cos(3t)*sin(t) For cos: cos(3t)*cos(t)-sin(3t)*sin(t) Considering that, I want to say that this is not an identity.
OpenStudy (anonymous):
sin3t=sin(2t+t)=sin2tcost+cos2tsint cos3t=cos(2t+t)=cos2tcost-sin2tsint
OpenStudy (anonymous):
plug them in the left side of the equation, you will get:
OpenStudy (anonymous):
|dw:1375657402157:dw|
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