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If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000.
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consider 3+6+9+......+999 multiples of 3 <1000 here a=3, d=3, l=999 l=a+(n-1)d,find n \[thenS3=\frac{ n \left( a+l \right) }{ 2 }\] similarly consider 5+10+15+...+995 here a=5,d=5,l=995 ,find n and then S5 again consider 15+30+45+...+990 here a=15,d=15,l=990,find n and S15 required sum=S3+S5-S15
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