Question

Solve each equation on the interval [0, 2pi].
4sin^2-3=0
rewrite this equation so that it is expressed in terms of sin^2x=a, where a is a nonzero number.

Answer 1

\(\bf 4sin^2(x)-3=0 \ \ ?\)

Answer 2

\[\sin \Theta = \pm \frac{ \sqrt{3} }{ 2}\]

Answer 3

Just solve for all solutions on the unit circle regarding the angle \[\pi / 3\]

Answer 4

what do you mean by that? I really don't understand how to do this problem.

Answer 5

Here is a unit circle.. find out the rest of the angles