Question

how do you establish this identity (tan v+1)^2 +(tan v-1)^2 =2sec^2 v

Answer 1

expand the square, what do you get?

Answer 2

(tan v^2 +2tan v +1)+(tan^2-2tan+1)= 2tan^2 +1

Answer 3

+2 sorry

Answer 4

ok, factor 2 out, what do you get?

Answer 5

tan^2+1=sec^2

Answer 6

2 out , so it is 2 sec^2, right? there you go,

Answer 7

ok Thanks so much for your help
:)

Answer 8

wut wut. glad to hear!!