Your club is selling tickets for a game. On Monday the club sold 3 adult tickets and 1 child ticket for a total of $38.
On Tuesday the club sold 3 adult tickets and 2 child tickets for a total of $52. Find the price of a child ticket and an adult ticket.
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OpenStudy (blurbendy):
you have to set up 2 equations. the first one would be
3a + 1c = 38
can you come up with the equation for the second part?
OpenStudy (anonymous):
yes
OpenStudy (blurbendy):
okay, what do you get
OpenStudy (anonymous):
3a+2c=52
OpenStudy (blurbendy):
okay, so you have:
3a + 1c = 38
3a + 2c = 52
you can use the elimination method or substitution, your choice
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OpenStudy (anonymous):
im not real good at those
OpenStudy (blurbendy):
just pick one
OpenStudy (anonymous):
elimination
OpenStudy (blurbendy):
okay, so if we use the elimination method, we can eliminate 3a pretty easily from both equations by multiplying the entire first one by -1
OpenStudy (blurbendy):
what would that give you?
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OpenStudy (anonymous):
-3a-1c=-38
OpenStudy (blurbendy):
good, so now you have:
-3a-1c=-38
3a + 2c = 52
now add the equations together:
-3a-1c=-38
+
3a + 2c = 52
OpenStudy (blurbendy):
what do you get?
OpenStudy (anonymous):
2c=14
OpenStudy (anonymous):
1c
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OpenStudy (anonymous):
sry
OpenStudy (blurbendy):
yes, c = 14
OpenStudy (blurbendy):
so now that we know, c = 14, substitute c = 14 back in for c in the top equation
OpenStudy (anonymous):
kk
OpenStudy (blurbendy):
3a + 1(14) = 38
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OpenStudy (anonymous):
3a=26
OpenStudy (blurbendy):
38 - 14 = 24
OpenStudy (anonymous):
3a=8
OpenStudy (blurbendy):
3a = 24
a = 8
OpenStudy (anonymous):
lol thats what i meant :)
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