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Mathematics 21 Online
OpenStudy (anonymous):

What is the equation of this graph ?

HanAkoSolo (jamierox4ev3r):

can u attach a pic. of the graph?

OpenStudy (anonymous):

OpenStudy (anonymous):

This is a vertical hyperbola. Therefore, since the center is (0,0) a=9, and b=16 (calculatd from the foci) y^2/9 - x^2/16 = 1

OpenStudy (anonymous):

thanks so much !!!!

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