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find the factors of w^2-16
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The difference of 2 perfect squares: a^2 - b^2 is: (a - b)(a + b) Hint: find a number such that b^2 = 16, that will help you.
4 so it would be (w-4) (w+4)
:)
You got it! Good luck to you in all of your studies and thx for the recognition! @amandajensen
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