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the distance of a car from a certain intercection after T seconds is given by d(T)=16+5T-T^2. when (that is, for which values of T) is the car 16 units away from the reference point? Choose all that apply: A. T=0 B.T=1 C.T=3 D.T=5 E. never Can some one explain this to me?
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16 units away means that d = 16. Can you solve now?
no
So it would just be 0?
cannot be 0
okay im confused
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t is time, the car moves 16 units in 0 second? does it make sense?
ohhhhhhhhh yeah okay so A. and E. are wrong right? so that leaves B, C and D to figure... okay I think I know what to do now thank you!
A and D equal 16 in the equation...
Yay! A and D are right!
let me do something for you |dw:1374970555359:dw|
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