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given the function p decribed by p(x)=x^3-x, find p(-8)
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p(x) = x^3 - x p(-8) = (-8) ^3 - (-8) Now evaluate that. What do you get?
p(x)=x^3-x, find p(-8) by putting the value of x which is -8: p(-8)= (-8)^3-(-8) p(-8)= -512+8 p(-8)= 504
there is a -504
Thank you both. Imtiaz7 especially, that was what I was looking for. Have a good one
no problem mygumshurt.
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That's it. Thanks again. Be well
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