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idk i don't usually solve triangle problems...
@MayMay_69 \[\huge HD=\frac{1}{2}TU\]
do you understand that part?
@MayMay_69 understood that part that i have written above?
because H and D are mid points and when we join them we get the 1/2 of TU.
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likewise, \[\huge => HE=\frac{1}{2}VU\] \[\huge => DE=\frac{1}{2}TV\]
understood or not? @MayMay_69
so \[\huge HD=\frac{1}{2}TU\] so , we have to find the value of TE. and \[\huge TE=\frac{1}{2}TU\] so \[\huge TE=HD\] and HD=80 so TE=80
hope you understand. @MayMay_69
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