Question

Find the angle between the given vectors to the nearest tenth of a degree.

u = <6, -1>, v = <7, -4>

Answer 1

dot product:
\[u*v=|u||v|\cos\]
\[\cos \Theta =\frac{ u*v }{ |u||v|}\]
\[\Theta = \cos^{-1} \frac{ u*v }{ |u||v| }\]

\[<6,-1>*<7,-4>=<6*7,-1*-4>\]
\[|u|=|<6,-1>|=\sqrt{6^{2}+-1^{2}}\]
\[|v|=|<7,-4>|=\sqrt{7^{2}+-4^{2}}\]

Plug-in and solve for inverse cosine (rounding your answer to 1/10 of degree)

Answer 2

Correction:
\[<6,-1>*<7,-4>=6*7+(-1)*(-4)\]

Answer 3

is it 20.3

Answer 4

yes